5[b+1]=3[b+3]

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Solution for 5[b+1]=3[b+3] equation:


Simplifying
5[b + 1] = 3[b + 3]

Reorder the terms:
5[1 + b] = 3[b + 3]
[1 * 5 + b * 5] = 3[b + 3]
[5 + 5b] = 3[b + 3]

Reorder the terms:
5 + 5b = 3[3 + b]
5 + 5b = [3 * 3 + b * 3]
5 + 5b = [9 + 3b]

Solving
5 + 5b = 9 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
5 + 5b + -3b = 9 + 3b + -3b

Combine like terms: 5b + -3b = 2b
5 + 2b = 9 + 3b + -3b

Combine like terms: 3b + -3b = 0
5 + 2b = 9 + 0
5 + 2b = 9

Add '-5' to each side of the equation.
5 + -5 + 2b = 9 + -5

Combine like terms: 5 + -5 = 0
0 + 2b = 9 + -5
2b = 9 + -5

Combine like terms: 9 + -5 = 4
2b = 4

Divide each side by '2'.
b = 2

Simplifying
b = 2

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